Soluciones Codecademy Python. Condicionales y control de flujo. Parte 1

Vamos con el tema 4 del curso de Python de Codecademy . Soluciones del 2/15 al 8/15

2/15

# 17 < 328

bool_one = True..

# 100 == (2 * 50).

bool_two = True

# 19 <=  19

bool_three = True

# -22 >= -18

bool_four = False

# 99 != 98 + 1

bool_five = False

3/15

# (20 - 10) > 15

bool_one = False

# (10 + 17) == 3**16

bool_two = False

# 1**2 <= -1

bool_three = False

# 40 * 4 >= -4

bool_four = True

# 100 != 10**2

bool_five = False

4/15

#¡Hazme igual a True!

bool_one = 1==1

#¡Hazme igual a False!

bool_two = 1<-8

#¡Hazme igual a True!

bool_three = 5>3

#¡Hazme  igual a False!

bool_four = 6==7

#¡Hazme igual a True!

bool_five = 5==5

6/15

# False and False

bool_one = False

# -(-(-(-2))) == -2 and 4 >= 16**0.5

bool_two = False

# 19 % 4 != 300 / 10 / 10 and False

bool_three = False

# -(1**2) < 2**0 and 10 % 10 <= 20 - 10 * 2

bool_four = True

# True and True

bool_five = True

7/15

# 2**3 == 108 % 100 or 'Cleese' == 'Rey Arturo'

bool_one = True

# True or False

bool_two = True

# 100**0.5 >= 50 or False

bool_three = False

# True or True

bool_four = True

# 1**100 == 100**1 or 3 * 2 * 1 != 3 + 2 + 1

bool_five = False

8/15

# not True

bool_one = False

# not 3**4 < 4**3

bool_two = True

# not 10 % 3 <= 10 % 2

bool_three = True

# not 3**2 + 4**2 != 5**2

bool_four = True

# not not False

bool_five = False